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If I have 15psi pressure held in a container with a closing cap 1inch diameter = 15psi pushing against the cap
If I have a 2inch cap does the psi pushing against the cap double to 30psi because the cap is twice as big? Or stay the same as the internal pressure is set at 15psi?
I've been told it'll stay the same (15psi no mater what the cap size) and I believe this to be true, just trying to solve a daft office argument.
psi remains the same.
The force on the larger cap is 4 x greater, because its area is 4 x greater.
the above is the way that all hydraulic systems work in JCB's etc.
move a small dia item and you can increase the effective force by having a larger one at the other end.
the pressure remains the same cos its pre square inch - but the force on it doubles as the area doubles
15 lbs per square inch means every square inch. The PRESSURE stays the same no matter how big the cap. However the FORCE on the cap is four times as many newtons, cos there are four times as many square inches in it.
Pressure = force / area
double the diameter = four times the area = four times the force.
pressure = force / area
force = pressure x area
area = 0.8 x (Diameter squared)
Thank you!
Cap 1 sees 11.85 lbs of force, cap two sees 47.1.