For circular motion pi=4, not 3.14.
if we want to hold on to the currently teached wisdom that "angular velocity = 2 x PI x radius x linear velocity" we would have to change PI to the value 4.
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[i]pi = 4 makes the trails come alive[/i]
I thought it was 3?
I admire people who actually have the time and inclination to argue against rubbish like that.
So a ball in a circular tube is slowed down faster than one in a straight tube. Is that any surprise to anyone?
I was more surprised by him needing to insist that he wasn't in Mexico.
Isn't this just that same "squared circle" just rolled out?
currently teached
??
What has any of that got to do with Pi?
The ball that is "forced" around in a circle must be forced round in that circle by an external force, in this case, the walls of the looped plastic tube, applying a force vector that points towards the centre of that loop of tube. That force causes friction, which slows the ball down, so the ball traveling in straight line (that just has friction from it's mass only (Acting downwards) is decelerated less, so travels further in the same time period.
If he had measured the speed of the balls on exit, that would have been obvious. Funnily enough he didn't do that bit..........
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Ok, so the friction increases so much to slow it down by 20+%. Really? A metal sphere is not gonna deform to increase its contact patch.maxtorque - MemberThe ball that is "forced" around in a circle must be forced round in that circle by an external force, in this case, the walls of the looped plastic tube, applying a force vector that points towards the centre of that loop of tube. That force causes friction, which slows the ball down, so the ball traveling in straight line (that just has friction from it's mass only (Acting downwards) is decelerated less, so travels further in the same time period.
So repeat the experiment and measure their speed at exit. Report back
er, what about the soft plastic tube?
The force to displace the trajectory has to come from somewhere!
The original Troll Pi is better I think.
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