OK, long story short, my mate wants to make one of these;
http://www.skiliftportabletow.com/
and as Im the engineering student Ive been asked to do all the calculations, problem being Im stuck on the most basic equations.
OK, here we go.
Want to be able to pull someone weighing 120kg up a 30* slope at 4m/s.
Coefficient of friction of snow is U=0.14 (apparently).
F=mg = 1178N
Resultant = 1178cos30 = 1018
F(friction)=UR = 142.6N
So that means theres 142.6N acting of the guy down the slope, so 142.6N is going to be needed in the cable just to hold the guy stationary right?
So, from there, how do we work out the extra force needed to pull him up the slope at 4m/s? This is where Im being total blonde and cant work it out, f=ma doesnt work cos theres no acceleration (assuming its already started up and is travelling at a constant velocity).
Surely there must be an equation linking velocity, mass, and the force required to keep that velocity?
Any ideas?
Once we’ve got this sorted we can move onto what kind of gearing we need to get the required output force from the engine 😛
Ta, Duane.