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So I'm trying to calculate the difference from moving from +10 angle stem to a -6 angle (both 100mm). Given that its been long time since I did this I'm not sure of my technique, this is my approach
Trigonometry identities SOH CAH TOA
So I want to know the opposite side magnitude from the angle difference which is 16 degrees, I chose the tan identity assuming that stem length 100mm represented the adjacent side (A).
So A*tan(16) = O. This gives a displacement (opposite side size) of 30.06 mm. I'm not sure if this is correct, perhaps (if the triangle was inverted) stem length represents the hypotenuse, which case sin would apply and 100*sin(16) = -28.79 mm. It's not a big difference and but I just wondered what other people thought if this situation and if my approach was correct?
Thanks
Alex
If it were me, I'd just flip the 10 degree stem over and see how it felt first.
30mm sounds about right. Regardless of which one's actually right, if you can tell the difference of 1.27mm in real life, I would be quite surprised
I used that very calculator last week. Jolly useful.
Thank for the replies especially bish, that was indeed very useful, the results of that calculator were a drop of 26 mm and an increase of reach of 10 mm about what I'd calculated but closer with using the sin identity.
Now, how is my neck going to handle that change, that's a completely different question indeed thols2. Currently my bars feel a bit high and there was cheap stem which I've already bought (in transit) and I wanted to calculate the difference it would make for the fun and mental exercise.
So I want to know the opposite side magnitude from the angle difference which is 16 degrees,
That doesn't work.
Sohcahtoa requires a right angle so you have to calculate. The problem you put forth is an isosceles triangle so you have to divide it in two.
The 10degrees
The 6degrees
And sum them for the difference in relation to the seerer. You also have to calculate the effect of the head angle aswell.
That's also why you should have used sin by the way opposite and adjacent are connected to the 90degrees. The hypotenuse is always the longest side and connects the non 90 angles.
Sketching always helps.
It's not actually complicated when you see it drawn.
You just need to know a bit about triangles and circles.
It also gets closer as you drop it after it stops getting further away.( Drops below horizontal.)
And the numbers don't mean anything anyway unless you know what you are trying to achieve. I'd flip the stem.
joshvegas, thanks for that, sketching helps as you say, the aim of this question was mostly about the mental exercise. I hadn't considered it was an isosceles triangle I was working with when considering both angles joined together, thanks again for your reply. Enjoyed this process and learned something, successful endeavour in my estimation.
I'm impressed you understood my rambled post to be honest.
I agree it's a nice little thought problem. Initially seems simple but geometry does interesting things.
Well done for not just googling it. Have you retried it to get the numbers the website gave?