A wee teaser for you.
If you put 1 pound coin on the first square of a chess board, 2 pound coins on the 2nd square, 4 pound coins on the 3rd, 8 on the 4th, 16 on the 5th and so on…..how tall is the pile of coins on the 64th square.
Pound coin is 3.15mm thick.
Is it on a conveyer belt?
EDIT. 3.07 light years (apparently)
2^63 =~ 9 x 10^18
29053621916092543.7952m
More understandably (perhaps), 29053billion kilometers, which is about two and a half times the diameter of Pluto's orbit
Oops, several orders of magnitude out on Pluto's orbit. 3 light years is about right.
It's pile ON pounds here. 
Thats a Mahoooosive pile of dough(saw that word on here yesterday and wanted to use it), but still not as big as UK Debt.
***I just had to***
S.
Variation on the old grain of rice story.
where is this chess board?
Surely at a certain height, the mass of the piled coins would exert a combined downward pressure so high that it would liquify the metal in the bottom coin, meaning that however many more coins you put on top, the pile could get no higher... 
There isn't enough pound coins in circulation.
There isn't enough pound coins in circulation.
No there aren't....
Anyway, this is why I carry big denomination notes instead of coins.
42?
Is the answer less than the national debt that Gordon has saddled us with?
Z11, well before that height the laws of chaotic dynamics would insist that the stack falls over. If we are going to bring physics into it 
assuming it didnt topple... which number coin added to the final stack would cause the onset of deformation in the bottome coin?
Well, for elastic deformation one should be enough
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