Forum menu
Any mathematicians on-line today? I need assistance with a question, involving integration using substitution. I can do every example I have except this one. I keep on looking back to the rules of logarithms as I think that is a way forward but I can't get it.
So, can anyone tell me the steps to the resolution of integral 3^x dx? Unusually Wolfram Alpha doesn't help. I know the answer is 1/ln3.3^x+c.
The integration tables that I am meant to be using do not deal with this example, so I need to know how to rearrange the integrand. This is what I want help with!
Thanks, in anticipation.
Think of it like this
3^x
e^(xln3)
then you can integrate
1/ln3 * 3^x + c
Sorry if it doesn't make much sense, I just woke up.
Spot on realman, easy-as when you know how. Thanks.
Can I go back to bed then..