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The Monty Hall Problem – a simple maths/probability problem for you all……..

I already have a car, but I don’t have a goat. Does this change things?
Posted 6 years agoI rememvber watching some horizon thing about this with Alan Davies a while back, but he did it with toy cars and cups….
….i think the outcome was that probability says that when you get a choice like that, if you change your mind you win more often than if you don’t
Posted 6 years agoI could set my calendar with the regularity that this thread comes up.
Posted 6 years agoWhat are the chances of that, though?
Posted 6 years agoYes.
Posted 6 years agoNo mmmmm curried goat ðŸ™‚
Posted 6 years agoI made a fantastic curry goat last week. The spices I used were from a tin of Tesco Ras El Hanout rub which I ground up a bit more. It was flipping lovely.
And yes – in the 3box game, if you do it 100 times you will win more if you switch. But for a single instance there is no difference. The car stays where it is.
Posted 6 years agoAnd yes – in the 3box game, if you do it 100 times you will win more if you switch. But for a single instance there is no difference. The car stays where it is.
??? So your probability of winning the car is increased, but only if you play it more than once? That sounds a little dubious ðŸ˜•
Posted 6 years agoI don’t think it’s a particular spoiler to give the answer, because a percentage of people won’t believe you anyway. We discussed this at length here a few weeks back.
You double your chances (from one in three to two in three) by changing your mind when offered the choice.
Posted 6 years agoFox everyone by picking again but picking the same door as the first time.
Goats are nice anyhow.
Posted 6 years agoFox everyone with a goat? *blinks*
Posted 6 years agoAnyway, about this plane on a conveyor belt….
Posted 6 years agoWhich door is the fox behind?
Posted 6 years agoAfter talking about the film ’21’ in the pub last night, much argument ensued about the ‘Monty Hall Problem’. Not sure if its been done before on here but I thought it would be fun for you all to have a go at this problem. Two things though, if you’ve already done it then don’t try to be a hero by posting your prior knowledge answer here and don’t go straight to Google/Wikipedia – you’re only cheating yourself.
Here it is:
Suppose you’re on a game show, and you’re given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what’s behind the doors, opens another door, say No. 3, which has a goat. He then says to you, “Do you want to pick door No. 2?” Is it to your advantage to switch your choice?
Posted 6 years agoswitching is clearly better but Monty – who knows where the car is – might be a bit of a ****t and be trying to trick you into losing the car, so he can make more money from the show and sleep with impressionable women, so it’s not quite so straightforward…
Posted 6 years agoWho is Monty Hall? Why does he have a car full of goats?
Posted 6 years agowell whenever i’ve seen deal or no deal (ahem) if you change your mind you always loose more then if you don’t.
Posted 6 years agoDoesnt it depend if the host knows where the car is? If it does then you should swap. If he’s just randomly picking a door then not.
Posted 6 years agoAnd yes – in the 3box game, if you do it 100 times you will win more if you switch. But for a single instance there is no difference. The car stays where it is.
Wrong.
Posted 6 years agowhen you first pick you have a 1/3 chance of choosing door with car.
the other two doors have 2/3 chance.
i think if the host now picks a door and opens it to reveal a goat then the door that is left now has a 2/3 chance of the car being there.
so you are better off swapping.
Posted 6 years agoDoes this apply to switching boxes at the end of Deal or no Deal then too? *scratches head* ðŸ˜¯
Posted 6 years agoThis hurt my head the last time it came up here and I’m not getting involved again.
Posted 6 years agoIf 1 & 2 stay as they are then surely it wouldnt make any difference.
Posted 6 years agoThis is messing with my head…..
Posted 6 years ago
surely, regardless of how you got there, you now have a choice of two doors, behind one of which is a car.
The chance of it being behind either door is equal.
So how does swapping your choice, from one 50% choice to another, increase your odds of winning?
Like I say, it’s playing with my mind…This is the explanation I posted on the original thread.
On the first choice you have a one in three chance of making a correct choice, and a two in three chance of goating out.
When the host asks if you want to change your mind, what’s essentially happening is that you’re being offered to swap the one door you have for both of the other doors.
You both know one of the remaining two doors contains a goat, by opening a door (with his insider knowledge) the host simply confirms something you knew anyway. Changing your mind nets you both doors, the opening of one of them is a bit of very effective misdirection.
Posted 6 years agoDoes this apply to switching boxes at the end of Deal or no Deal then too? *scratches head*
Not really as the game is played differently and in some versions of the show the “banker” knows the value of each box and in others he/she doesn’t. There probably is some sort of mathematical model but it will be horrifically complicated.
Incidently you should probably deal at anything over Â£1000 as there is a only a 50% chance that your selected box will contain more than this amount, despite the fact that the mean prize is Â£26000ish
Posted 6 years agoThis principil only works if the host knows where the car is and takes away one of the goat options.
Basiclly you have a 66% chance of picking a goat in the first place. The host has to show you a goat so the remaining door has to be a car.
This only doesn’t work if you picked the car in the first instance, but as you only had a 33% chance of doing that then the numbers are in your favour.Rustler, it makes a difference as the host knows and is showing you a goat. That is not random it is calulated.
Posted 6 years agoThe OP states that the host knows where the car is.
Which, TBH, is pretty much a prerequisite, otherwise he could open door number three and accidentally find that the car is there, buggering the entire premise.
Posted 6 years agoCougar. well put, good explanation
Posted 6 years agoThank you (:
Posted 6 years agoI understand the maths/theory behind this and i understand Cougars explanation and it makes sense. I also believe it to be correct but my head just refuses to accept it!
Posted 6 years agoOK, say there were 1000 doors, 999 had goats behind and 1 had the car.
You choose one of the doors – so a 1 in 1000 chance of being a car. Host then opens 998 doors with goats behind leaving one unopened door.
Would you change doors now ? ðŸ™‚
Posted 6 years agoI also believe it to be correct but my head just refuses to accept it!
… which is the entire point of the puzzle. It’s to show that our intuition isn’t to be trusted.
There’s a number of other explanations on the earlier thread I linked to ^^ there, if it helps.
Posted 6 years agoall the pies, same principal but even more important to switch
Your 1st choice had a 0.1% chance of being correct
swapping gives you a 99.9% of winning.
As Cougar said your swapping your 1 door for 999 doors but knowing which of those 999 doors are goats.
Posted 6 years agoSorry to the people have seen this on here before – I come on here a bit but it was the first time I’d heard about it last night in the pub
Posted 6 years agosurely, regardless of how you got there, you now have a choice of two doors, behind one of which is a car.
Yes.
The chance of it being behind either door is equal.
No.
Just because there are two possbible outcomes doesn’t mean that they are equally likely. If you were to by a lottery ticket there are two possible outcomes; you will either win the jack pot, or you won’t. The odds of you winning the jackpot aren’t 50:50.
Posted 6 years agoSo with the 1 in 1000 example, after he has showed you the goats are behind the other 998 doors so youre left with youre door and 1 onther door the odds of the car being behind the other door and not your door are 99.9% despite the fact you know you have 2 options, 1 being a goat and 1 being a car?
Posted 6 years ago
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