Fundamentally Shred is correct – the force pulling the tyre off the rim is lower with a narrower tyre. However the calcs are wrong, as you appear to have got a squared term in there when the area of the tyre is actually directly proportional to the width, not proportional to the square of the width (area ~= pi * width * circumference).
It is also higher with a wider tyre. Look at it like this, imagin chopping the tyre in half at the point the sidewalls are vertical – with a 25mm tyre the upward force due to the pressure at this point is pressure * 25mm, which is shared between the two beads. With a 50mm tyre the upward force due to pressure at this point is pressure * 50mm, which is still shared between the two beads (OK I know we should be looking at an area not a linear dimension to convert pressure to force, but the circumference dimension does not change for these calcs – not only that, but the tension in the carcass is a force per unit length rather than a spot force). This is the tension in the carcass which directly translates to the force at the bead.
Does nobody here own a Notubes rim? Have you not spotted that the max pressure varies with tyre width – this is the reason.
Though to come back to the original point, there is no way I would run a tubeless road tyre at 100psi on a rim not designed for it.