Viewing 15 posts - 1 through 15 (of 15 total)
  • Maths homework help
  • thekingisdead
    Free Member

    Trying to “help” with some maths revision, its been along time since I’ve done anything like this.

    Can anyone help with the following:

    3(2x + 4) = 5x + 17

    I’ve got this far:

    3(2x + 4) = 5x + 17
    6x + 12 = 5x +17
    6x = 5x + 5

    So *if* I’m correct thus far Im confident that x = 5. But i wouldn’t be certain how to show my working.
    And I’m not that confident Im actually correct 🙄

    Thanks

    gauss1777
    Free Member

    That’ll do and you can be sure you’re correct as 5 satisfies the original equation.

    You’re a natural 🙂

    i_like_food
    Full Member

    Spot on

    kormoran
    Free Member

    ‘shudders’

    🙁

    thekingisdead
    Free Member

    what would be the step to get from

    6x = 5x + 5
    to
    x = 5

    for the purposes of explanation…
    I know its x = 5 in my head, but cant show how i arrived at that

    theotherjonv
    Full Member

    The only ‘improvement’ (and it would be very marginal) is that your last bit is inferred as opposed to shown:

    6x = 5x + 5

    Subtract 5x from both sides

    => 6x-5x = 5

    X = 5

    slowster
    Free Member

    Unless I’m hopelessly out of date, I would expect that they would want to see the intermediate workings, which if things have remained unchanged since I was at school (unlikely), would mean something like this:

    6x + 12 = 5x + 17
    6x – 5x = 17 – 12
    x = 5

    thekingisdead
    Free Member

    Thanks all!
    Might be back later with some more! :-/

    willej
    Full Member

    Remember to try and get all the variables on the left of the = and the numbers on the right. I’m sure there’s probably a name for that process…

    theotherjonv
    Full Member

    sod off – we’ve shown you how to do it, you’re on your own now.

    (can someone help my daughter with % calcs. I can do them but I can’t explain adequately to get her to see it. Seriously; it’s not the calcs themselves, it’s knowing when to use which:

    eg: Polly sees a dress in the shop. The label price is £15 but there is a special offer of 20% off. How much does the dress cost?

    Ans: £15 x 20% = £3, therefore dress is 15-3 = £12
    (or – 20% off means you pay 100-20 = 80%. £15 x 80% = £12)

    vs

    Polly buys a dress in the 20% off sale. She pays £12 for the dress, what was the original price.

    Ans: £12 / 0.8 = £15

    But she keeps using £12 x 1.2 to find the original price = £14.40 = wrong.

    vs: Polly buys a dress in America and can claim the sale tax of 6.5% back. The price she pays is $15.97, what was the cost of the dress without tax

    Ans: $15.97 / 1.065 = $15

    scaredypants
    Full Member

    But she keeps using £12 x 1.2 to find the original price = £14.40 = wrong.

    get her to do a really obvious one like 50% discount on a tenner – with real pound coins

    RobHilton
    Free Member

    gauss1777

    Interesting user name on a maths thread 🙂

    theotherjonv
    Full Member

    she can do the first no probs, it’s flipping it to back calculate it.

    And in fact if I get her to do the first one first she then sees the second. But give her the second in isolation, she has a mental block.

    gauss1777
    Free Member

    “Polly buys a dress in the 20% off sale. She pays £12 for the dress, what was the original price.

    Ans: £12 / 0.8 = £15″

    I like your method best,

    perhaps a slight tweak to 0.8x=12
    x=12/0.8
    X=15. where x is the original amount would make it clearer why you divided?

    but I have often seen it taught:

    80%——— 12
    1%————12/80=0.15
    100%———-100×0.15=15

    Hope that’s clear.

    Oh and Rob, I’m a Gauss fanboi – as they say

    theotherjonv
    Full Member

    Ta, will try it.

Viewing 15 posts - 1 through 15 (of 15 total)

The topic ‘Maths homework help’ is closed to new replies.