wheel rotation invokes swingarm rotation when the brake is applied.
(the ground skidding past the tyre is an input force, which acts around the pivot, the swingarm rotates).
your seesaw model is not valid.
sorry.
let's say you're slowing at 0.1g, and weigh aroudn 100Kg, the force at the tyre/ground contact patch will be 100N.
100N acting at a distance equal to the height of the pivot above the ground (0.35m)= 35Nm.
and that's 35Nm of compressing torque - not insignificant (based on 0.1g)

